Hi,

Strange post, I hope someone can help. My girlfriend has 2 unlinked genetic conditions which affect her ability to get pregnant, hold the baby to full term and give birth to a natural baby. She is 40 years old and there is a 50% chance she will pass one of these conditions on and she is wanting to go 'forward' with IVF but I am hoping to convince her otherwise but I wanted to give her some real stats before we decide.

So. how do I calculate the overall chance of a healthy baby.

e.g.

a) there is a 50% chance she will pass on one genetic condition

2) She has a 30% chance of having a down syndrome baby

3) She has a 25% chance pass of passing on the other genetic condition

4) she has a 20% chance of stillborn

So how do I calculate the overal probability of a giving birth to a healthy child, assuming she has how problems in pregnancy.

Is it 100% a) =50% , b)15%(2 conditions so odds /2, 3) 8.33 (3rd condition so odds/3) = 73.3% = 26.7% ?

Please help, I'm exhausted. Maths only please. I'm too tired for opinions..Her condition also dictates that there are multiple reasons why she could miscarry so in laymens terms if someone could explain the logic I would really appreciatte it. Please assume I am dumb.

Strange post, I hope someone can help. My girlfriend has 2 unlinked genetic conditions which affect her ability to get pregnant, hold the baby to full term and give birth to a natural baby. She is 40 years old and there is a 50% chance she will pass one of these conditions on and she is wanting to go 'forward' with IVF but I am hoping to convince her otherwise but I wanted to give her some real stats before we decide.

So. how do I calculate the overall chance of a healthy baby.

e.g.

a) there is a 50% chance she will pass on one genetic condition

2) She has a 30% chance of having a down syndrome baby

3) She has a 25% chance pass of passing on the other genetic condition

4) she has a 20% chance of stillborn

So how do I calculate the overal probability of a giving birth to a healthy child, assuming she has how problems in pregnancy.

Is it 100% a) =50% , b)15%(2 conditions so odds /2, 3) 8.33 (3rd condition so odds/3) = 73.3% = 26.7% ?

Please help, I'm exhausted. Maths only please. I'm too tired for opinions..Her condition also dictates that there are multiple reasons why she could miscarry so in laymens terms if someone could explain the logic I would really appreciatte it. Please assume I am dumb.

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