question of sequences and series

r267747

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Oct 1, 2009
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I don't know how to find the equations of the bisectors of the angles between the coordinate axes
 
The angles between the x and y axes is 90 degrees.
Bisecting those, we get 45 degree angles for the lines.
One line goes up and the other goes down, they go through the origin.
If we go up 1 horizontally, we go down 1 vertically for the line with negative slope
(characteristic of a triangle with 45 degree angle).
If we go up 1 horizontally, we go up 1 vertically for the other line.

Slopes are 1 and -1.

Line equations are y=mx, since c=0.

Hence the lines are y=x and y=-x.
 
chrisr said:
The angles between the x and y axes is 90 degrees.
Bisecting those, we get 45 degree angles for the lines.
One line goes up and the other goes down, they go through the origin.
If we go up 1 horizontally, we go down 1 vertically for the line with negative slope
(characteristic of a triangle with 45 degree angle).
If we go up 1 horizontally, we go up 1 vertically for the other line.

Slopes are 1 and -1.

Line equations are y=mx, since c=0


SIR,FOR LINES GO UP AND DOWN THROUGH THE ORIGIN, PLEASE SHOW DIAGRAM
 
A vertical line through the origin?

x = 0

When you say bisector between the axes, do you mean bisector between the positive x-axis and the negative x-axis?
 
r267747 said:
I don't know how to find the equations of the bisectors of the angles between the coordinate axes
sir i am not an intelligent student so that i can understand your hints.I am an average one so, please briefly explainsir please solve this question for me.
(answer is y=+x,y=-x)
 
I don't know what you want.

Do you want a graph of y = x and y = -x ?

Do you understand chrisr's explanation?
 
Uh-oh!!

I posted the diagram on your other thread r267747.
been a bit tired lately, too much travelling.

[attachment=0:1mmliim5]bisectors.jpg[/attachment:1mmliim5]

here it is again
 

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