Queuing theory: At a computerized Rail Reservation window, the customer arrivals are considered to be Poisson with an average inter-arrival time of...

Win_odd Dhamnekar

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At a computerized Rail Reservation window, the customer arrivals are considered to be Poisson with an average inter-arrival time of ten minutes. The railway clerk's time for serving the customer (examination of reservation slip, making reservation, collecting cash and issuing reservation ticket) may be assumed to be distributed negative exponentially with an average of 6 minutes.

(a)What is the chance the customer will straightaway get a ticket without having to wait in line?

(b)For what part of time will the railway clerk be busy?

(c)Find the average queue length, average number of customers in the system, average waiting time of a customer and the average time a customer spends in the system.

(d)There is a complaint the waiting time of an arrival exceeds 45 minutes and an additional clerk is required. Determine how large the new arrival rate should be to justify a second clerk?

How can we answer these questions? I am working on these questions. If any member knowing the correct answers to all of these question, may reply.
 
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