J jtw2e2 New member Joined Sep 3, 2009 Messages 45 Apr 23, 2010 #1 This is part of an optimization problem actually... My function is A(y)=((-3/2)y + 200)y Do I use the product rule to find this derivative?
This is part of an optimization problem actually... My function is A(y)=((-3/2)y + 200)y Do I use the product rule to find this derivative?
D Deleted member 4993 Guest Apr 23, 2010 #2 jtw2e2 said: This is part of an optimization problem actually... My function is A(y)=((-3/2)y + 200)y Do I use the product rule to find this derivative? Click to expand... Yes A'(y) = [-1.5y + 200] - 1.5y = 200 + 3y
jtw2e2 said: This is part of an optimization problem actually... My function is A(y)=((-3/2)y + 200)y Do I use the product rule to find this derivative? Click to expand... Yes A'(y) = [-1.5y + 200] - 1.5y = 200 + 3y
J jtw2e2 New member Joined Sep 3, 2009 Messages 45 Apr 25, 2010 #3 Subhotosh Khan said: jtw2e2 said: This is part of an optimization problem actually... My function is A(y)=((-3/2)y + 200)y Do I use the product rule to find this derivative? Click to expand... Yes A'(y) = [-1.5y + 200] - 1.5y = 200 + 3y Click to expand... Thank you.
Subhotosh Khan said: jtw2e2 said: This is part of an optimization problem actually... My function is A(y)=((-3/2)y + 200)y Do I use the product rule to find this derivative? Click to expand... Yes A'(y) = [-1.5y + 200] - 1.5y = 200 + 3y Click to expand... Thank you.