does anyone know how to write 16^-3/4 in radical notation? im stuck on this
i actually figured that part out now im trying to figure out how to evaluate the expression nowI'll do a different but similar problem for you:
\(\displaystyle (125)^{\frac{-2}{3}} \ = \ \dfrac{1}{\sqrt[3]{125^2}}\)
i actually figured that part out now im trying to figure out how to evaluate the expression now
If you give the factors of 125 some thought, the cube root should be clear.
Claudette, you must use grouping symbols, such as in "16^(-3/4)." Also, for appropriate numbers, as in this case, the expression is equivalent to: \(\displaystyle \ \ \dfrac{1}{(\sqrt[4]{16})^3} \) \(\displaystyle \ \ \ \ \ Continue \ \ with \ \ that.\)does anyone know how to write 16^-3/4 in radical notation? im stuck on this