Radical?

[paris567]

hello, i figured out this question but I'm not sure how to verify it properly. could someone verify this question for me =?
i end up with 6 but when i substitute the 6 with the x I'm not sure

question:

 

[lev888]

hello, i figured out this question but I'm not sure how to verify it properly. could someone verify this question for me =?
i end up with 6 but when i substitute the 6 with the x I'm not sure

question:

View attachment 24222

Please post your entire solution, not just the answer.

 

[Romsek]

[MATH]\large{ \sqrt[3]{2x-7} - 5 = 0\\ \sqrt[3]{2x-7} = 5\\ 2x-7 = 5^3 = 125\\ 2x = 132\\ x = 66}[/MATH]

 

[JeffM]

Your answer is clearly wrong.

[MATH]2 \cdot 6 - 7 = 12 - 7 = 5.[/MATH]
Do you realy think that if you multiply 5 * 5 * 5 you will get 5?

We cannot help you if you show no work. That is the only way we can see where you went wrong and help you learn.