OKAY! NOW! I have figured the squareroot symbol stuff out!
I hope this clears things up for everyone (and keeps you from getting
annoyed with my confusing typing!!)
If anyone could tell me if I am on the right track or totally messing this up
I would greatly appreciate it!
Also the last couple of problems I have no idea where to start, so if some one could tell me what to do to get started, or the first step or two(asap!) I would REALLY REALLY appreciate it!
Okay, here they are-
1.Multiply and simplify:
\(\displaystyle \sqrt{8X^2} * \sqrt{8X^3}\)
My attempt:
\(\displaystyle \sqrt{64X^5}\)
\(\displaystyle \sqrt{8X^5}\)
\(\displaystyle \sqrt{8X^4X}\)
Final answer=\(\displaystyle \8X^4 sqrt{X}\)
2. Multiply and simplify: \(\displaystyle \sqrt{6y^2} * \sqrt{3y^3}\)
I multiplied \(\displaystyle \6y^2\) and \(\displaystyle \3y^3\) and ended up with \(\displaystyle \sqrt{18y^5}\) for final answer? Is this right?
3. Solve: X-1= \(\displaystyle \sqrt{X+5}\)
My notes said to square everything:
\(\displaystyle (X-1)^2\)=(\(\displaystyle \sqrt{X+5}\))^2
\(\displaystyle X^2-1=X+5\)
I subtracted X from each side and then:
\(\displaystyle X^2-X-1=5\)
I then subtracted 5 from each side and then:
\(\displaystyle X^2-X-6=0\)
I found the two numbers that would multiply to equal
-6, and add to equal X(or 1)
(X-3)(X+2)
Set to equal zero=
X=3 or X=-2
4. Solve:
\(\displaystyle 4+ \sqrt{X-3}\)=11
Started out trying to subtract 4 from both sides like my lecture notes
were showing me,but could not come up with a good answer, if anyone could give me a suggestion as of how to get started that would be great!
5. Solve: \(\displaystyle \sqrt{2-X} = \sqrt{3X-7}\)
I have no idea where to start on these last two(#3 and #4). From my instructor's lecture notes, I know I am to end up with 2 answers that I have to set to equal zero. I understand that part, just I am having a hard time getting started on the first part of the problems!, I have made attempts and keep getting stuck! help!
I hope this clears things up for everyone (and keeps you from getting
annoyed with my confusing typing!!)
If anyone could tell me if I am on the right track or totally messing this up
I would greatly appreciate it!
Also the last couple of problems I have no idea where to start, so if some one could tell me what to do to get started, or the first step or two(asap!) I would REALLY REALLY appreciate it!
Okay, here they are-
1.Multiply and simplify:
\(\displaystyle \sqrt{8X^2} * \sqrt{8X^3}\)
My attempt:
\(\displaystyle \sqrt{64X^5}\)
\(\displaystyle \sqrt{8X^5}\)
\(\displaystyle \sqrt{8X^4X}\)
Final answer=\(\displaystyle \8X^4 sqrt{X}\)
2. Multiply and simplify: \(\displaystyle \sqrt{6y^2} * \sqrt{3y^3}\)
I multiplied \(\displaystyle \6y^2\) and \(\displaystyle \3y^3\) and ended up with \(\displaystyle \sqrt{18y^5}\) for final answer? Is this right?
3. Solve: X-1= \(\displaystyle \sqrt{X+5}\)
My notes said to square everything:
\(\displaystyle (X-1)^2\)=(\(\displaystyle \sqrt{X+5}\))^2
\(\displaystyle X^2-1=X+5\)
I subtracted X from each side and then:
\(\displaystyle X^2-X-1=5\)
I then subtracted 5 from each side and then:
\(\displaystyle X^2-X-6=0\)
I found the two numbers that would multiply to equal
-6, and add to equal X(or 1)
(X-3)(X+2)
Set to equal zero=
X=3 or X=-2
4. Solve:
\(\displaystyle 4+ \sqrt{X-3}\)=11
Started out trying to subtract 4 from both sides like my lecture notes
were showing me,but could not come up with a good answer, if anyone could give me a suggestion as of how to get started that would be great!
5. Solve: \(\displaystyle \sqrt{2-X} = \sqrt{3X-7}\)
I have no idea where to start on these last two(#3 and #4). From my instructor's lecture notes, I know I am to end up with 2 answers that I have to set to equal zero. I understand that part, just I am having a hard time getting started on the first part of the problems!, I have made attempts and keep getting stuck! help!
