rainfall

RajS

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Help:
Rain falls at an average of 1mm/hr over an 8ha area 3.5 days. a) determine the total depth of rain in cm that fell over the 8ha area, b) the average rate of rainfall over the area I'm m³ s‐¹
 
Help:
Rain falls at an average of 1mm/hr over an 8ha area 3.5 days. a) determine the total depth of rain in cm that fell over the 8ha area, b) the average rate of rainfall over the area I'm m³ s‐¹
I would first calculate:

how many hours are there in 3.5 days? And

how many m2 are there in 1 ha ?

Please show us what you have tried and exactly where you are stuck.

Please follow the rules of posting in this forum, as enunciated at:


Please share your work/thoughts about this problem.
 
3.5days 84hrs
84 x 1.2 mm 100.8mm ÷ 10 = 10cm
1.2mm= 0.0012m
1ha = 80,000m² ............................................................................................Incorrect
80,000÷0.0012 = 96 .....................................................................................Incorrect
M³s‐¹ =96/60 = 1.6 m³ s
 
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The 3rd part of the question asked for: determine the total volume of water that fell in m³
 
I would first calculate:

how many hours are there in 3.5 days? And

how many m2 are there in 1 ha ?

Please show us what you have tried and exactly where you are stuck.

Please follow the rules of posting in this forum, as enunciated at:


Please share your work/thoughts about this problem.
Please see thread
 
Help:
Rain falls at an average of 1mm/hr over an 8ha area 3.5 days. a) determine the total depth of rain in cm that fell over the 8ha area, b) the average rate of rainfall over the area I'm m³ s‐¹
3.5days 84hrs
84 x 1.2 mm 100.8mm ÷ 10 = 10cm
1.2mm= 0.0012m
1ha = 80,000m² ...........................................Incorrect
80,000÷0.0012 = 96 ...........................................Incorrect
M³s‐¹ =96/60 = 1.6 m³ s
depth of Total rainfall = rate * time = 1 * 80 [mm/hr] * hr = 80 mm

1 ha = 104 m2

Now what.....
 
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