Random Number Generator Problem, All Help Appreciated :)

skypilot

New member
Joined
Sep 11, 2017
Messages
2
Hello forum please help me with this problem,

I'm trying to catch a pokemon (yes please bear with me) whose has 6 attributes, each attribute is given a random number value ranging from 0 to 31 (32 possible results). An example would be 0/ 31/ 28/ 12/ 3/ 20. Each ot the attribute value is randomly generated and independent of each other.

However I'm able to manipulate any 3 of the 6 attributes to be garuanteed 31. Any meaning in no particular where they are garuanteed to be 31. An example of this would be: 31/ 31/ 31/ 0/ 20/ 7 or 31/ 11/ 8/ 31/ 31/ 2. Again the 3 remaining random numbers are independently generated & no effect on each other.

So my questions are:

1) What is the probability that out of the three remaining attributes I will get 2 more 31? An example would be 31/31/31/31/7/31? I've seen discusstion where people put the odds to be 1/200, now I understand that even if I catch 200 pokemons I might not get one with 5 perfect 31, so would catching 400 increase the probability of catching one with 5 attribute of 31?

2) What is the probability of catching a pokemon with a random generated attributes of all 31? Meaning all 6 attributes? i.e 31/31/31/31/31/31?

Thank you very much for your time and please help me out!
 

Subhotosh Khan

Super Moderator
Staff member
Joined
Jun 18, 2007
Messages
18,572
Hello forum please help me with this problem,

I'm trying to catch a pokemon (yes please bear with me) whose has 6 attributes, each attribute is given a random number value ranging from 0 to 31 (32 possible results). An example would be 0/ 31/ 28/ 12/ 3/ 20. Each ot the attribute value is randomly generated and independent of each other.

However I'm able to manipulate any 3 of the 6 attributes to be garuanteed 31. Any meaning in no particular where they are garuanteed to be 31. An example of this would be: 31/ 31/ 31/ 0/ 20/ 7 or 31/ 11/ 8/ 31/ 31/ 2. Again the 3 remaining random numbers are independently generated & no effect on each other.

So my questions are:

1) What is the probability that out of the three remaining attributes I will get 2 more 31? An example would be 31/31/31/31/7/31? I've seen discusstion where people put the odds to be 1/200, now I understand that even if I catch 200 pokemons I might not get one with 5 perfect 31, so would catching 400 increase the probability of catching one with 5 attribute of 31?

2) What is the probability of catching a pokemon with a random generated attributes of all 31? Meaning all 6 attributes? i.e 31/31/31/31/31/31?

Thank you very much for your time and please help me out!
Is 1/ 31/ 31/ 0/ 20/ 7 different from Is 31/ 1/ 31/ 0/ 20/ 7?
 

skypilot

New member
Joined
Sep 11, 2017
Messages
2
Is 1/ 31/ 31/ 0/ 20/ 7 different from Is 31/ 1/ 31/ 0/ 20/ 7?
Yes although they have the same total value, each stats of the two pair are generated differently.
 
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