#### diogomgf

##### Junior Member

- Joined
- Oct 19, 2018

- Messages
- 62

I'm struggling with this exercise:

Find the possible ranks of the matrix D, depending on the values of a and b.

\(\displaystyle D_{a,b} = \begin{bmatrix}a & -1 & 1 & b \\0 & 1 & a & 1 \\1 & 0 & 2 & 2 \\0 & 1 & 1 & a\end{bmatrix}\)

After reducing D to row echelon form I got:

\(\displaystyle \begin{bmatrix}1 & 0& 2& 2 \\0 & 1 & a & 1\\0& 0 & 1-a& b-2a+1\\0 & 0& 0& b-a\end{bmatrix}\)

Based on this I concluded that if \(\displaystyle a = 1 \) and \(\displaystyle b = 1 \) then \(\displaystyle r(D) = 2 \); If \(\displaystyle a = b \) and \(\displaystyle a,b \neq 1 \) then \(\displaystyle r(D) = 3 \).

Apparently this is incorrect according to the solutions in the book, and I can't really understand why.

Find the possible ranks of the matrix D, depending on the values of a and b.

\(\displaystyle D_{a,b} = \begin{bmatrix}a & -1 & 1 & b \\0 & 1 & a & 1 \\1 & 0 & 2 & 2 \\0 & 1 & 1 & a\end{bmatrix}\)

After reducing D to row echelon form I got:

\(\displaystyle \begin{bmatrix}1 & 0& 2& 2 \\0 & 1 & a & 1\\0& 0 & 1-a& b-2a+1\\0 & 0& 0& b-a\end{bmatrix}\)

Based on this I concluded that if \(\displaystyle a = 1 \) and \(\displaystyle b = 1 \) then \(\displaystyle r(D) = 2 \); If \(\displaystyle a = b \) and \(\displaystyle a,b \neq 1 \) then \(\displaystyle r(D) = 3 \).

Apparently this is incorrect according to the solutions in the book, and I can't really understand why.

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