Rate-Time-Distance Prob: At 9:30, he left E for P at 12 mph

Tweetiegal9

New member
Joined
Nov 15, 2007
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1
At 9:30a.m. Andrew left Exeter for Portsmouth, cycling at 12 mi/h. At 10:00a.m.Stacy left Portsmouth for Exeter, cycling at 16mi/h. The distance from Exeter to portsmouth is 20 mi. Find the time when they meet.
 

skeeter

Senior Member
Joined
Dec 15, 2005
Messages
2,396
when they meet, Andrew will have traveled a distance d, and Stacy will have traveled a distance 20-d.

Andrew will have traveled a time t (in hours), and Stacy will have traveled a time t-(1/2).

now use {rate * time = distance} to write two equations in terms of t and d ... then solve the system of equations.
 

royhaas

Full Member
Joined
Dec 14, 2005
Messages
832
Here's another way to look at it. Andrew has traveled 6 miles when Stacy starts, so together they must cover the remaining 14 miles. Since they are traveling towards each other, you can add their rates and figure out the time it takes.
 
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