Ratio-1
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Please post 1 problem/thread
Please show us what you have tried and exactly where you are stuck.
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https://www.freemathhelp.com/forum/threads/read-before-posting.109846/#post-486520
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Steven G
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You have to try something especially if you want to receive help from this forum.
You do not know how many sweets Andy and Marc start with each.
So let A = the number of sweets that Andy starts with and Let M = the number of sweets that Marc starts with.
Then A + M = 105 is one equation. Can you figure out the other equation? Then solve for A.
You do not know how many sweets Andy and Marc start with each.
So let A = the number of sweets that Andy starts with and Let M = the number of sweets that Marc starts with.
Then A + M = 105 is one equation. Can you figure out the other equation? Then solve for A.
HallsofIvy
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Start by "naming" the things you want to find:
let a be the number of sweets Andy had and let m be the number of sweets marc had. They had 105 sweets altogether so a+ m= 105.
Now "interpret" each statement as an algebraic quantity.
"Andy ate 4/5 of his sweets". So he ate 4/5 of a, 4a/5 and had a- 4a/5= 5a/5- 4a/5= a/5 left.
"Marc ate 3/5 of his sweets". So he at 3/5 of m, 3m/5 and had m- 3m/5= 5m/5- 3m/5= 2m/5 left.
"In the end, the number of sweets Marc had left was 4/5 the number of sweets Andy had left."
This where we get the equation. Marc had 2m/5 sweets left and that was (was equal to) 4/5 of the number of sweets Andy had left. Andy had a/5 sweets left and 4/5 of that is (4/5)(a/5)= 4a/25.
2m/5= 4a/25. The first thing I would do is divide both sides by 2: m/5= 2a/25. Then get rid of the fractions by multiplying both sides by 5m= 2a.
So we have a+ m= 105 and 5m= 2a. From a+ m= 105, we see that a= 105- m. So 5m= 2(105- m)= 210- 2m. Surely you can finish.
let a be the number of sweets Andy had and let m be the number of sweets marc had. They had 105 sweets altogether so a+ m= 105.
Now "interpret" each statement as an algebraic quantity.
"Andy ate 4/5 of his sweets". So he ate 4/5 of a, 4a/5 and had a- 4a/5= 5a/5- 4a/5= a/5 left.
"Marc ate 3/5 of his sweets". So he at 3/5 of m, 3m/5 and had m- 3m/5= 5m/5- 3m/5= 2m/5 left.
"In the end, the number of sweets Marc had left was 4/5 the number of sweets Andy had left."
This where we get the equation. Marc had 2m/5 sweets left and that was (was equal to) 4/5 of the number of sweets Andy had left. Andy had a/5 sweets left and 4/5 of that is (4/5)(a/5)= 4a/25.
2m/5= 4a/25. The first thing I would do is divide both sides by 2: m/5= 2a/25. Then get rid of the fractions by multiplying both sides by 5m= 2a.
So we have a+ m= 105 and 5m= 2a. From a+ m= 105, we see that a= 105- m. So 5m= 2(105- m)= 210- 2m. Surely you can finish.