Example 1:
There are 2 Big Identical Groups, but they are split into 6 groups (3 and 3) .
Group 1.
Group A (6), Group B (6), Group C (6).
Group 2.
Group A. (6) , Group B(6) , Group C (6).
Group A= 4*1 , 4*2 ... 4*6, Group B = 8*1, 8*2, 8*6, Group C= 12*1, 12*2.... 12*6.
You want to land Group C , 6th option, in both Group 1 and Group 2. It yields the biggest reward. What are the odds you land on C(6) on both groups same time.
In this instance , since Group 1 has a chance of 18 possible outcomes, and group 2 has the same exact 18 chance. would you simply do 18*18=1:324 Chance?
Example 2.
You keep that same 1/2 Groups
But you add 2 more groups that have just 2 chances (these two groups identical
Group 1(2)
Group 2( 2).
So here you want to land (#2) in both groups 1 and 2 at the same time, while landing Group C #6 in both groups from above
2*2*18*18=1:1296? Correct?
There are 2 Big Identical Groups, but they are split into 6 groups (3 and 3) .
Group 1.
Group A (6), Group B (6), Group C (6).
Group 2.
Group A. (6) , Group B(6) , Group C (6).
Group A= 4*1 , 4*2 ... 4*6, Group B = 8*1, 8*2, 8*6, Group C= 12*1, 12*2.... 12*6.
You want to land Group C , 6th option, in both Group 1 and Group 2. It yields the biggest reward. What are the odds you land on C(6) on both groups same time.
In this instance , since Group 1 has a chance of 18 possible outcomes, and group 2 has the same exact 18 chance. would you simply do 18*18=1:324 Chance?
Example 2.
You keep that same 1/2 Groups
But you add 2 more groups that have just 2 chances (these two groups identical
Group 1(2)
Group 2( 2).
So here you want to land (#2) in both groups 1 and 2 at the same time, while landing Group C #6 in both groups from above
2*2*18*18=1:1296? Correct?
Last edited: