- Thread starter Miles
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If y is bigger than x by 1/8th of x, thenHi

I'm doing a maths reasoning practice question and I'm wondering why in the solution an eighth is translated as 1 1/8 instead of just 1/8. Please see enclosed.

Plus, can someone point me in the right direction where I can read up on this.

Many thanks

MView attachment 9234

\(\displaystyle y = x + \dfrac{1}{8} * x \equiv \left (1 + \dfrac{1}{8} \right ) * x \equiv \dfrac{9x}{8}.\)

Just different ways to get the same arithmetic result. Really nothing to read up on.

Thanks Jeff, but I need to practice more of these to get a better understanding, so what subject would this come under algebra?If y is bigger than x by 1/8th of x, then

\(\displaystyle y = x + \dfrac{1}{8} * x \equiv \left (1 + \dfrac{1}{8} \right ) * x \equiv \dfrac{9x}{8}.\)

Just different ways to get the same arithmetic result. Really nothing to read up on.

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This is the same concept as "percent increase". Reading about that may help.Thanks Jeff, but I need to practice more of these to get a better understanding, so what subject would this come under algebra?

Or, as Jeff showed, it just comes from applying algebra to the problem: "

Ah! Now I get it. ThanksThis is the same concept as "percent increase". Reading about that may help.

Or, as Jeff showed, it just comes from applying algebra to the problem: "increasex by fraction m" means "addm times x to x itself" (start with x, andincreaseit by m times itself).

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Fractions and percentages are usually pre-algebra, or before pre-algebra.Thanks Jeff, but I need to practice more of these to get a better understanding, so what subject would this come under algebra?