evaluate (8^4/5)^5/6 125^1/3 divded by 27^1/3 please help me
tkhunny Moderator Staff member Joined Apr 12, 2005 Messages 11,339 Nov 27, 2005 #2 Use these rules: (a^b)^c = a^(b*c) a^b / a^c = a^(b-c) That's about all you need. Well, I guess you may also need: 2^3 = 8 3^3 = 27 5^3 = 125
Use these rules: (a^b)^c = a^(b*c) a^b / a^c = a^(b-c) That's about all you need. Well, I guess you may also need: 2^3 = 8 3^3 = 27 5^3 = 125
D Denis Senior Member Joined Feb 17, 2004 Messages 1,707 Nov 27, 2005 #3 CARIRAMOS said: evaluate (8^4/5)^5/6 =8^(20/30) : multiply exponents =8^(2/3) =8^2^(1/3) =64^(1/3) =4 : ^(1/3) means cube root 125^1/3 divded by 27^1/3 = 5/3 : 5*5*5=125; 3*3*3=27 why were you having problems with that one? please help me Click to expand...
CARIRAMOS said: evaluate (8^4/5)^5/6 =8^(20/30) : multiply exponents =8^(2/3) =8^2^(1/3) =64^(1/3) =4 : ^(1/3) means cube root 125^1/3 divded by 27^1/3 = 5/3 : 5*5*5=125; 3*3*3=27 why were you having problems with that one? please help me Click to expand...
