chesterdg123
New member
- Joined
- Jun 9, 2008
- Messages
- 21
Hi, I have received feedback that I have not finished the following rational inequality, any feedback will be appreciated. Thanks!
x/(x-5)<2
x/(x-5)-2=0
(x-5){x/(x-5)-2}=(x-5).0
x-2x+10=0
-x+10=0
-x=-10
x=10
The critical values are 5, and 10, They divide the x-axis into the intervals: (-00, 5), (5, 10), and (10, 00)
(-00, 5) f(4)=-6
(5, 10) f(6)=4
(10, 00) f(15)= -0.5
The function values are positive on (5, 10) and it is the solution set.
x/(x-5)<2
x/(x-5)-2=0
(x-5){x/(x-5)-2}=(x-5).0
x-2x+10=0
-x+10=0
-x=-10
x=10
The critical values are 5, and 10, They divide the x-axis into the intervals: (-00, 5), (5, 10), and (10, 00)
(-00, 5) f(4)=-6
(5, 10) f(6)=4
(10, 00) f(15)= -0.5
The function values are positive on (5, 10) and it is the solution set.