- Thread starter Moistwh
- Start date

- Joined
- Nov 12, 2017

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Please show your work, so we can see what you did wrong. Your result

We'll be looking for what your u and v are, and how you carried out the details.

- Joined
- Nov 12, 2017

- Messages
- 3,650

But the integral of e^{x^2} dx is not e^{x^2}/{2x}. In fact, it can't be integrated! Check your work here by differentiating.

The fact that the derivative of e^{x^2} is 2x e^{x^2} does not mean that the derivative of e^{x^2}/{2x} is e^{x^2}.

Instead, try taking u = x^{n-1} and dv = x e^{x^2} dx, which can be easily integrated.