Region bounded by graphs URGENT please(:

[xc14]

Sketch the Region bounded by the graphs of f(x)=sinx and g(x)=(sqrt(3))/2 on the interval [0, pi/2]

I just need help with finding the interval to integrate and the how to get to integral. The trigonometry is really messing me up.
Any help greatly appreciated:grin:

 

[Davecobra96]

Alright, so to take the integral between two curves then you must know which function is above the other. The sqrt(3)/2 is the same as sine pi/3. So you have to integrate from 0 to pi/3 using g(x) - f(x). Then you have to integrate from pi/3 to pi/2 using f(x)- g(x). The function with the highest value comes first in the integral. Hope I could help, good luck!

 

[Quaid]

Sketch the Region bounded by the graphs of f(x)=sinx and g(x)=(sqrt(3))/2 on the interval [0, pi/2]

Is this part of the exercise, or is this what you're asking us to do for you?

I just need help with finding the interval to integrate and the how to get to integral. The trigonometry is really messing me up.

I would start with a graph of the situation.

Have you been asked to calculate the combined area of the two regions described above?

The only trigonometry that I see is sin(x). What have you done so far?

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Thank you