K kareemy New member Joined Feb 28, 2010 Messages 1 Feb 28, 2010 #1 Find the area of the region inside spiral r=4? and outside the circle r=2sin?. any help with this question would be greatly appreciated, i have no idea how to even begin to approach it
Find the area of the region inside spiral r=4? and outside the circle r=2sin?. any help with this question would be greatly appreciated, i have no idea how to even begin to approach it
G galactus Super Moderator Staff member Joined Sep 28, 2005 Messages 7,203 Feb 28, 2010 #2 Graphing always helps. Find the area from 0 to pi/2 and double it. \(\displaystyle \int_{0}^{\frac{\pi}{2}}\left[(4t)^{2}-(2sin(t))^{2}\right]dt\) Attachments spiral.jpg 26 KB · Views: 123
Graphing always helps. Find the area from 0 to pi/2 and double it. \(\displaystyle \int_{0}^{\frac{\pi}{2}}\left[(4t)^{2}-(2sin(t))^{2}\right]dt\)
