related rates word problems

rmsbu

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Oct 8, 2014
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If two resistors with resistances R1 and R2 are connected in parallel, as in the figure below, then the total resistance R, measured in ohms (Ω), is given by
1
R
=
1
R1
+
1
R2
.

If R1 and R2 are increasing at rates of 0.3 Ω/s and 0.2 Ω/s, respectively, how fast is R changing when R1 = 100 Ω and R2 = 110 Ω?
 
...If R1 and R2 are increasing at rates of 0.3 Ω/s and 0.2 Ω/s, respectively, how fast is R changing when R1 = 100 Ω and R2 = 110 Ω?
When you say R1 is increasing at rates of 0.3 Ω/s, the formula for R1 becomes
R1 = R10 + 0.3 t
where t is in seconds. Similarly for R2
R2 = R20 + 0.2 t
So, given that
(\(\displaystyle \frac{1}{F}\))' = \(\displaystyle \frac{-F'}{F^2}\)
and
\(\displaystyle \frac{1}{R}\) = \(\displaystyle \frac{1}{R_1}\) + \(\displaystyle \frac{1}{R_2}\)
what is R' when R1 = 100\(\displaystyle \Omega\) and R2 = 110\(\displaystyle \Omega\)

Edit: Not thinking clearly - made a bad assumption and had to delete it.
 
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