Relative rates

R

Ramulala

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I am stuck on this problem, as far as I know I did it right. Please help me with this
 

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Is the answer about 40.21? Maybe the -0.4 rate for diameter should become -0.2 for radius?
 
Last edited:
[imath]\dfrac{d}{dt}(D = 2r) = \dfrac{dD}{dt} = 2\dfrac{dr}{dt} \implies \dfrac{dr}{dt} = \dfrac{1}{2} \cdot \dfrac{dD}{dt}[/imath]
 
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