Ummmm..."show work please"???KingAce said:What's the removable and nonremovable discontinuities in the equation below?
(x-2)/(x^2 + x - 6)
(show work please!!!)![]()
Your work is correct.KingAce said:Here's my work, and here's my answers:
(x-2)/(x^2+x-6)
(x-2)/(x-2)(x+3)
=1/(x+3)
removable x = 2 nonremovable x = -3