mathdad
Full Member
- Joined
- Apr 24, 2015
- Messages
- 737
The price p (in dollars) and the quantity x sold of a certain product obey the demand equation: x = -20p + 500, where
0 is less than p which is less than or equal to 25.
A. Express the revenue R as a function of x.
Note: use R = px
x = -20p + 500
x - 500 = -20p
(x - 500)/(-20) = p
(-x/20) + 25 = p
R = px
R = [(-x/20) - 25]x
R = (-x^2)/20 + 25x
B. What is the revenue if 20 units are sold?
Let x = 20
R = (-(20)^2)/20 + 25(20)
R = -400/20 + 625
R = -20 + 625
R = 605
Is this right?
0 is less than p which is less than or equal to 25.
A. Express the revenue R as a function of x.
Note: use R = px
x = -20p + 500
x - 500 = -20p
(x - 500)/(-20) = p
(-x/20) + 25 = p
R = px
R = [(-x/20) - 25]x
R = (-x^2)/20 + 25x
B. What is the revenue if 20 units are sold?
Let x = 20
R = (-(20)^2)/20 + 25(20)
R = -400/20 + 625
R = -20 + 625
R = 605
Is this right?