rewriting function y=x^2-4x+6 and finding the vertex

Maryjo

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Apr 26, 2009
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I need to rewrite each function in the form y=a(x-h)squared +k

y=x^2-4x+6
 


Please show any work that you can accomplish, and try to say something about WHY you're stuck, so that people might determine where to begin helping you.

If you are totally lost, then please CLICK HERE and read about the process called "completing the square". Work through the examples.

Once you learn enough to understand how to start, then try your exercise. Feel free to post specific questions here, if you need any clarification of examples or you get stuck.

Check out the post titled, "Read Before Posting"; it outlines your responsibilities for seeking help here.

Cheers 8-)

 
Maryjo said:
I need to rewrite each function in the form y=a(x-h)squared +k

y=x^2-4x+6
If they gave you a formula for finding the vertex (namely, h = -b/(2a) and k = f(h)), then use that formula to find the coordinates of the vertex.

Then find a point on the graph (such as by letting x = 0, so y = 6, so you have the point (x, y) = (0, 6)), and plug that point and the vertex into the "vertex form" of the equation. Solve for "a". :wink:
 
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