I am sure the answer to this is simple, but for some reason I can't get started.
I have been given that ABCD is a parallelogram with <1 congruent to <2 ( Angle BAD that has been bisected). I am to prove that If a dagonal of a parallelogram bisects and angle of the parallelogram, the parallelogram is a rhombus.
The only other angle marked on the diagram is angle 3, which is half of angle BCD, and in the traingle ACB. WHat should be my plan? I know that if I can show angle 3 congruent to angle 2, I can show that all the sides are congruent, but how do I do that? Thanks!
I have been given that ABCD is a parallelogram with <1 congruent to <2 ( Angle BAD that has been bisected). I am to prove that If a dagonal of a parallelogram bisects and angle of the parallelogram, the parallelogram is a rhombus.
The only other angle marked on the diagram is angle 3, which is half of angle BCD, and in the traingle ACB. WHat should be my plan? I know that if I can show angle 3 congruent to angle 2, I can show that all the sides are congruent, but how do I do that? Thanks!