michaelcaba
New member
- Joined
- Jan 25, 2020
- Messages
- 29
This one stumps me. Can anyone show me their steps to the solution, which is 2.5 seconds.
A rock is thrown straight up into the air from a height of 4 feet. The height of the rock above the ground in feet, t seconds after it is thrown is given by −16t^2+56t+4. For how many seconds will the height of the rock be at least 28 feet above the ground?
A rock is thrown straight up into the air from a height of 4 feet. The height of the rock above the ground in feet, t seconds after it is thrown is given by −16t^2+56t+4. For how many seconds will the height of the rock be at least 28 feet above the ground?