Runge-Kutta

Areti Kassi

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Sep 2, 2021
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How do I calculate y(0.3) with the method Runge-Kutta 4th order when 3dy/dx +xy^2= sinx, y(0) =5 and h=0.3?

I get 4,66 but the possible answers are
1. 0.88
2. - 0.05
3. - 3,61
4. - 7,25*10^8IMG_20210902_224426.jpg
 
Last edited:

Please share your steps that resulted in 4,66. Thank you!

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How do I calculate y(0.3) with the method Runge-Kutta 4th order when 3dy/dx +xy^2= sinx, y(0) =5 and h=0.3?

I get 4,66 but the possible answers are
1. 0.88
2. - 0.05
3. - 3,61
4. - 7,25*10^8View attachment 28742
While calculating sin(x), the value of 'x' is in radians (not degrees). More specifically, if you are calculating "this" with a calculator, make sure it is in "radian" mode.
 
While calculating sin(x), the value of 'x' is in radians (not degrees). More specifically, if you are calculating "this" with a calculator, make sure it is in "radian" mode.
Thanks for the advice but I think I did that correctly because I used Google for the sinx and it automatically is in radian mode
 
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