Hello,
I am stuck on this problem:
A, B, C and D are four points such that:
[MATH]\overrightarrow{BA} [/MATH] ⋅ [MATH]\overrightarrow{BD}[/MATH] ≤ 0 and [MATH]\overrightarrow{DB} [/MATH] ⋅ [MATH]\overrightarrow{DC}[/MATH] ≤ 0
Prove that AC ≥ BD.
Thanks for your help!
I am stuck on this problem:
A, B, C and D are four points such that:
[MATH]\overrightarrow{BA} [/MATH] ⋅ [MATH]\overrightarrow{BD}[/MATH] ≤ 0 and [MATH]\overrightarrow{DB} [/MATH] ⋅ [MATH]\overrightarrow{DC}[/MATH] ≤ 0
Prove that AC ≥ BD.
Thanks for your help!