I got a problem in Geometry that deals with tangents and secants.
My problem has one tangent and secant, the tangent is located at the top of the circle and the secant is a little bit down from the circle. I am asked to solve for x. The secant and the tangent intersect outside the circle and that intersection would be x degrees. Next they give me the inner arc which is 63 degrees and the outer arc is equal to 5x degrees.
I have to use the theorem that says that the measure of angle x equals one-half of the outer arc minus the inner arc. I am having trouble getting the outer arc. Could someone please help me. :?
Thanks in advance
My problem has one tangent and secant, the tangent is located at the top of the circle and the secant is a little bit down from the circle. I am asked to solve for x. The secant and the tangent intersect outside the circle and that intersection would be x degrees. Next they give me the inner arc which is 63 degrees and the outer arc is equal to 5x degrees.
I have to use the theorem that says that the measure of angle x equals one-half of the outer arc minus the inner arc. I am having trouble getting the outer arc. Could someone please help me. :?
Thanks in advance