Try to calculate the following equation from dx/dy = 1/y' :
1)d^2x/dy^2 = -y''/(y')^3
Hello, I am taking a calculus course in my university. I am not very good in it, so I apologize if my question is too 'dumb'.
Here is how I've been trying to solve this question:
I tried multiplying the first equation ( dx/dy = 1/y') by the integrating factor, and then integrate it, but for me it didn't work, I am sure I am doing something wrong. I also tried to find a number that satifies both equations, like a number N that the second derivative is equal to N^3, but that is also wrong too..
I feel like I keep hitting a wall when trying to solve it, so I will be thankful if anyone can help
1)d^2x/dy^2 = -y''/(y')^3
Hello, I am taking a calculus course in my university. I am not very good in it, so I apologize if my question is too 'dumb'.
Here is how I've been trying to solve this question:
I tried multiplying the first equation ( dx/dy = 1/y') by the integrating factor, and then integrate it, but for me it didn't work, I am sure I am doing something wrong. I also tried to find a number that satifies both equations, like a number N that the second derivative is equal to N^3, but that is also wrong too..
I feel like I keep hitting a wall when trying to solve it, so I will be thankful if anyone can help