A) 2 of the first 4 eggs inspected are rotten.

If I think the probability of getting 4 rotten eggs in order then it will be (4/12)*(3/11)*(2/10)*(1/9) right?

but I really can't think to solve this problem,,it's been a while I studied it...

B)The third egg to be inspected is the first rotten one found.

so this mean the first two eggs have to be the normal ones and the third one inspected will be the first rotten one.

C)The last rotten egg is the tenth egg to be inspected.

Among 4 rotten eggs, 3 rotten eggs were found during the 9 inspection

What kind of probability thereom do I need to use to solve this kind of question?

please help me!!