sequence

Vali

Junior Member
Joined
Feb 27, 2018
Messages
87
I have the following sequence \(\displaystyle (x_{n})_{n\geq 1}\) ; \(\displaystyle x_{n+1}=x_{n}^2-x_{n}+1\)
If \(\displaystyle x_{100}=1\) then \(\displaystyle x_{2}=?\)
 

Vali

Junior Member
Joined
Feb 27, 2018
Messages
87
I did it.I got the response 1.
In the second exercise I need to find \(\displaystyle x_{1}\) such that \(\displaystyle (x_{n})_{n\geq 1}\) is convergent.
 

pka

Elite Member
Joined
Jan 29, 2005
Messages
8,670
I have the following sequence \(\displaystyle (x_{n})_{n\geq 1}\) ; \(\displaystyle x_{n+1}=x_{n}^2-x_{n}+1\)
If \(\displaystyle x_{100}=1\) then \(\displaystyle x_{2}=?\)
In the second exercise I need to find \(\displaystyle x_{1}\) such that \(\displaystyle (x_{n})_{n\geq 1}\) is convergent.
If \(\displaystyle x_1=1\) then \(\displaystyle x_2=~?,~x_3=~?~\&~x_{100}=~?\)
Now you carry on.
 
Top