sequence

Vali

Junior Member
Joined
Feb 27, 2018
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87
I have the following sequence (xn)n1\displaystyle (x_{n})_{n\geq 1} ; xn+1=xn2xn+1\displaystyle x_{n+1}=x_{n}^2-x_{n}+1
If x100=1\displaystyle x_{100}=1 then x2=?\displaystyle x_{2}=?
 
I did it.I got the response 1.
In the second exercise I need to find x1\displaystyle x_{1} such that (xn)n1\displaystyle (x_{n})_{n\geq 1} is convergent.
 
I have the following sequence (xn)n1\displaystyle (x_{n})_{n\geq 1} ; xn+1=xn2xn+1\displaystyle x_{n+1}=x_{n}^2-x_{n}+1
If x100=1\displaystyle x_{100}=1 then x2=?\displaystyle x_{2}=?
In the second exercise I need to find x1\displaystyle x_{1} such that (xn)n1\displaystyle (x_{n})_{n\geq 1} is convergent.
If x1=1\displaystyle x_1=1 then x2= ?, x3= ? & x100= ?\displaystyle x_2=~?,~x_3=~?~\&~x_{100}=~?
Now you carry on.
 
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