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- Thread starter pkwiz
- Start date

- Joined
- Jun 18, 2007

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- 25,824

Please show us what you have tried andWe have 6 levels of cards - levels 1, 2, 3, 4, 5 and 6.

If 5 cards of one level = 2 of the next level

and 3 cards of one level = 1 of the next level ,

how many level 1 cards minimum would it take to get to a level 6 card?

Please follow the rules of posting in this forum, as enunciated at:

Please share your work/thoughts about this problem.

By my calculations it would take 125 level 1 cards minimum to get to level 6. I'm not sure if that's correct though so I would appreciate it if somebody double checks this.Please show us what you have tried andexactlywhere you are stuck.

Please follow the rules of posting in this forum, as enunciated at:

Please share your work/thoughts about this problem.

- Joined
- Jan 1, 2022

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- 48

We can write a recursive formula:

[math]A_{n}=A_{n-1}\cdot\frac{2}{5}[/math]

To get 1 six you would need 3 5's.

We can write a recursive formula:

[math]A_{n}=A_{n-1}\cdot\frac{2}{5}[/math]

To get 3 5's you would need 8 4's (5 to get two and 3 to get 1 more).

To get 8 4's you would need 20 3's.

To get 20 3's you would need 50 2's.

To get 50 2's you would need 125 1's.

- Joined
- Oct 29, 2019

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To get 1 six you would need 3 5's.

To get 3 5's you would need 8 4's (5 to get two and 3 to get 1 more).

To get 8 4's you would need 20 3's.

To get 20 3's you would need 50 2's.

To get 50 2's you would need 125 1's.

I agree with your work, so well done, but I found your presentation a little hard to follow. I'd suggest that you write it like this:-

To get 1 on level 6 you would need 3 on level 5.

To get 3 on level 5 you would need 8 on level 4 (5 to get two and 3 to get 1 more).

To get 8 on level 4 you would need 20 on level 3.

To get 20 on level 3 you would need 50 on level 2.

To get 50 on level 2 you would need 125 on level 1.

Or even better:-

Code:

```
Level number of cards
6 1
5 3
4 8
3 20
2 50
1 125
```