daniele002
New member
- Joined
- Dec 11, 2020
- Messages
- 8
hey! thank you for replyingWhat happens if alpha > 4/3??
For n > 1, 1+n^5 < n^5 + n^5 = 2n^5. Also ln(n) < n for n>0. Does this help?
I do not know. What do you think? Why would it converge for alpha > 4/3? More importantly why would you think that it converge if alpha <4/3. Why did you leave out the case when alpha = 4/3?hey! thank you for replying
so would it diverge for alpha<4/3 and converge for alpha>4/3?
for alpha>4/3I do not know. What do you think? Why would it converge for alpha > 4/3? More importantly why would you think that it converge if alpha <4/3. Why did you leave out the case when alpha = 4/3?
if ln(n)<n and 1+n^5<2n^5 then ln(1+n^5)<2n^5 right?How did you get (log(1+n^5)+n^3a+n^2)/(n^4+2)≤(2n^5+n^3a)/(n^4)