KindofSlow
Junior Member
- Joined
- Mar 5, 2010
- Messages
- 90
Assignment is to set up (don't have to solve) triple integral for space above the plane 2x + y + 3z = 6 and below the plane z=2.
Also, to show that order doesn't matter, to set it up as dV = dz dx dy.
For the dz limits, I got the correct answer of - from 2 - 2/3x - y/3 up to 2.
For the dx limits, I got the correct answer of - from 0 up to 3 - y/2.
So good so far.
For the dy limits, I got from 0 up to 6-2x.
The book says this should be from 0 up to 6.
I cannot figure out why the upper dy limit is 6 instead of 6 - 2x.
Any explanation or clarification will be greatly appreciated.
Thank you
Also, to show that order doesn't matter, to set it up as dV = dz dx dy.
For the dz limits, I got the correct answer of - from 2 - 2/3x - y/3 up to 2.
For the dx limits, I got the correct answer of - from 0 up to 3 - y/2.
So good so far.
For the dy limits, I got from 0 up to 6-2x.
The book says this should be from 0 up to 6.
I cannot figure out why the upper dy limit is 6 instead of 6 - 2x.
Any explanation or clarification will be greatly appreciated.
Thank you