shooting at a target

[amal_]

"Three people A,B and C practice shooting at a target .The probability that A ,B and C hit the target is 0.9,0.8,0.6 , respectively .Now select any one of them at random ,what is the probability that the person selected hits the target ?"
I found this question to be a little bit confusing ,would that imply calculating the probability that they hit the target given that they are A +the probability that they hit the target given that they are B+ the probability that they hit the target given that they are C?

 

[pka]

"Three people A,B and C practice shooting at a target .The probability that A ,B and C hit the target is 0.9,0.8,0.6 , respectively .Now select any one of them at random ,what is the probability that the person selected hits the target ?"

If the target is hit then either A, B, or C will have done the deed, So that is a partition of the space.
[imath]\mathcal{P}(A)\left(\dfrac{1}{3}\right)=(0.9)\left(\dfrac{1}{3}\right)[/imath] is the probability that [imath]A[/imath] is chosen, shoots, and hits the target.

 

[Steven G]

Add, then divide by3.