Given a parallelogramm ABCD with the diagonal intersection point M, such that the circumcircle of the triangle ABM intersects the line AD in a point E (different from A) and the circumcircle of the triangle EMD intersects the line BE in a point F (different from E).
Show that the angles ACB and DCF are equal.
I have provided a visualisation of the problem, but I don't even know where to start. I'd love to hear all your ideas on this one
Show that the angles ACB and DCF are equal.
I have provided a visualisation of the problem, but I don't even know where to start. I'd love to hear all your ideas on this one
