W waseemshahzada New member Joined Jan 28, 2012 Messages 1 Jan 28, 2012 #1 show that the curvature of a circle of radius 'a' equals 1/a plz help me if any body can solve it plz
show that the curvature of a circle of radius 'a' equals 1/a plz help me if any body can solve it plz
pka Elite Member Joined Jan 29, 2005 Messages 11,978 Jan 28, 2012 #2 waseemshahzada said: show that the curvature of a circle of radius 'a' equals 1/a Click to expand... Let \(\displaystyle r(t)=a\cos(t)+a\sin(t)\) be a circle of radius \(\displaystyle a\). Then \(\displaystyle \bf{T}(t)=\dfrac{r'(t)}{\|r'(t)\|}\). Then curvature is \(\displaystyle \kappa(t)=\dfrac{\|\bf{T}'(t)\|}{\|r'(t)\|}\). Now you do the work.
waseemshahzada said: show that the curvature of a circle of radius 'a' equals 1/a Click to expand... Let \(\displaystyle r(t)=a\cos(t)+a\sin(t)\) be a circle of radius \(\displaystyle a\). Then \(\displaystyle \bf{T}(t)=\dfrac{r'(t)}{\|r'(t)\|}\). Then curvature is \(\displaystyle \kappa(t)=\dfrac{\|\bf{T}'(t)\|}{\|r'(t)\|}\). Now you do the work.