Simple calc problem!!

brant1mj

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Feb 7, 2012
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Use a graph of f or some other method to determine what, if any, value to assign to f(a) to make f continuous at x = a. HINT [See Example 2.] (If there is no such value, enter NONE.)

f(x)= x/6x^2-x ; a = 0
 
Use a graph of f or some other method to determine what, if any, value to assign to f(a) to make f continuous at x = a. HINT [See Example 2.] (If there is no such value, enter NONE.)

f(x)= x/6x^2-x ; a = 0

Obviously, 0 is not in the domain of this function, as it would cause the denominator to equal zero.

Factor the denominator. Simplify by canceling like terms in the numerator and denominator. Aha, there is a "hole" at f(0). Plot the simplified function, leaving a hole at zero.

For some good examples and explanations, check these out:

http://www.purplemath.com/modules/grphrtnl4.htm

http://www.sparknotes.com/math/algebra2/specialgraphs/section2.rhtml
 
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