medicalphysicsguy
New member
- Joined
- Jan 23, 2012
- Messages
- 28
Greetings,
Chapter 1, my DQ textbook asks us to evaluate potential solutions to:
\(\displaystyle \frac{dy}{dt}=\frac{y+1}{t+1}\)
It says
\(\displaystyle y = t^2-2\)
is not a solution.
But I get:
\(\displaystyle \frac{t^2-1}{t+1} = \frac{(t+1)(t-1)}{t+1} = t-1\)
therefore
\(\displaystyle dy = (t-1)dt\)
or
\(\displaystyle y = \frac{1}{2}t^2 - t\)
Can anyone tell me what is wrong with my math here?
Thanks,
Eric
Chapter 1, my DQ textbook asks us to evaluate potential solutions to:
\(\displaystyle \frac{dy}{dt}=\frac{y+1}{t+1}\)
It says
\(\displaystyle y = t^2-2\)
is not a solution.
But I get:
\(\displaystyle \frac{t^2-1}{t+1} = \frac{(t+1)(t-1)}{t+1} = t-1\)
therefore
\(\displaystyle dy = (t-1)dt\)
or
\(\displaystyle y = \frac{1}{2}t^2 - t\)
Can anyone tell me what is wrong with my math here?
Thanks,
Eric