Simplify 6x^3y^2 - 4x^2y / 8xy + 12x^3y^2

[yohanson77]

Hello again,
It has been a month since my last question

This has me well and truelly stumped?

Simplify the following fraction:

6x^3y^2 - 4x^2y / 8xy + 12x^3y^2

Scary!

Hope someone can help

 

[soroban]

Re: Simplify Fraction?

Hello, yohanson77!

If you mean: \(\displaystyle \L\:\frac{6x^3y^2\,-\,4x^2y}{8xy\,+\,12x^3y^2}\)

factor and reduce: \(\displaystyle \L\:\frac{\not{2}\cdot x^{\not2}\cdot\not{y}\cdot\left(3xy\,-\,2)}{\not{4}_2\cdot\not{x}\cdot\not{y}\cdot\left(2\,+\,3x^2y)} \:=\:\frac{x(3xy\,-\,2)}{2(2\,+\,3x^2y)}\)

 

[yohanson77]

That is exactly how I meant.

It all comes flooding back, it's easy once shown.

Thanks for the quick reply, it's much appreciated.

This site is great

 

[Denis]

6x^3y^2 - 4x^2y / 8xy + 12x^3y^2

If Soroban's is what you meant, then you need BRACKETS:
(6x^3y^2 - 4x^2y) / (8xy + 12x^3y^2)

Without brackets, then it goes this way:
6x^3y^2 - 4x^2y / 8xy + 12x^3y^2
= 18x^3y^2 - 4x^2y / 8xy
= 18x^3y^2 - x / 2
= (36x^3y^2 - x) / 2
= x(36x^2y^2 - 1) / 2