Simplify an expression

SilverKing

New member
Joined
Dec 25, 2013
Messages
23
Hi everyone,

I've the following expression:
6y8hFco.png
To:
RgZdGnp.png
_______________
My try:
9*[-100(y^2 - 4y + 29)^3/2 + 180 (y^2 + 2y + 69)^3/2
______________________________________________ = 0
(y^2 + 2y + 69)^3/2 (y^2 - 4y + 29)^3/2

-900(y^2 - 4y + 29)^3/2 + 1620 (y^2 + 2y + 69)^3/2 = 0

And I'm stuck in here.

Hope you can help.
 
I've the following expression:
View attachment 3938
To:
View attachment 3939

Hi SilverKing:

What is the meaning of To: ?

Are you thinking that the two expressions quoted above are the same?

The graph of the quadratic polynomial is a parabola; the graph of the given expression is not, even if epsilon_0 equals 1/(36000000000Pi) -- as you seem to think.

Can you post the entire exercise?

Cheers :)
 
Last edited:
Thank you for your responds, and sorry for disturbing.

I guess I missed a point, this is the exercise:

iFGuLdQ.jpg
 
So you could have posted simply:

180 / [13 + (y - 4)^2]^(3/2) - 100 / [65 + (y + 2)^2]^(3/2)] = 0

Solve for y.

Yes?

Assuming no multiplication by zero

100^(2/3) * [13 + (y - 4)^2] = 180^(2/3) * [65 + (y + 2)^2]

This will reduce to some quadratic equation....
 
Aha, I think I got it now, my problem was how to eliminate the power of ^(3/2), looks like you multiply both side by 1^(2/3)

Thank you very much, everyone, I really appreciate you help. :)
 
...my problem was how to eliminate the power of ^(3/2), looks like you multiply both side by 1^(2/3)
No. To "cancel" a power of 3/2 on one side of an equation, one must raise both sides to the power 2/3. ;)
 
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