- Thread starter alsacecat
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. . . . .i<sup>0</sup> = 1

. . . . .i<sup>1</sup> = i

. . . . .i<sup>2</sup> = -1

. . . . .i<sup>3</sup> = -i

. . . . .i<sup>4</sup> = 1

. . . . .i<sup>5</sup> = i

. . . . .i<sup>6</sup> = -1

. . . . .i<sup>7</sup> = -i

. . . . .i<sup>8</sup> = 1

...so that every fourth power (i<sup>0</sup>, i<sup>4</sup>, i<sup>8</sup>, etc) returns you to "1". How did you relate this to "i<sup>27</sup> = i<sup>24+3</sup> = i<sup>24</sup> i<sup>3</sup>"?

Thank you.

Eliz.

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It was explained and demonstrated previously that i<sup>24</sup> = 1. So you have been given:alsacecat said:ok so now i still have -1, by doing this

i^24+3=i^24i^3=-1. Better?

. . .i<sup>27</sup> = i<sup>24+3</sup>

. . . .. .= i<sup>24</sup> i<sup>3</sup>

. . . .. .= (1)(i<sup>3</sup>)

. . . .. .= i<sup>3</sup>

Is i<sup>3</sup> equal to -1?

Eliz.