R royhaas Full Member Joined Dec 14, 2005 Messages 832 Aug 17, 2009 #2 Your expression may be ambiguous but perhaps \(\displaystyle 3(x+1)^{5/3}\) is a common factor.
D Denis Senior Member Joined Feb 17, 2004 Messages 1,700 Aug 17, 2009 #3 lmkeefe70 said: 3/5(x+1)^5/3 Click to expand... Can you bit a bit clearer :shock: Is that (3/5) times (x + 1)^5 divided by 3 ? If so, this makes it clear: [(3/5)(x + 1)^5] / 3
lmkeefe70 said: 3/5(x+1)^5/3 Click to expand... Can you bit a bit clearer :shock: Is that (3/5) times (x + 1)^5 divided by 3 ? If so, this makes it clear: [(3/5)(x + 1)^5] / 3
L lmkeefe70 New member Joined Aug 17, 2009 Messages 2 Aug 17, 2009 #4 Denis said: lmkeefe70 said: 3/5(x+1)^5/3 Click to expand... Can you bit a bit clearer :shock: Is that (3/5) times (x + 1)^5 divided by 3 ? If so, this makes it clear: [(3/5)(x + 1)^5] / 3 Click to expand... Sorry the problem is:3/5(x+1)^5/3 + 3/4(x+1)^8/3
Denis said: lmkeefe70 said: 3/5(x+1)^5/3 Click to expand... Can you bit a bit clearer :shock: Is that (3/5) times (x + 1)^5 divided by 3 ? If so, this makes it clear: [(3/5)(x + 1)^5] / 3 Click to expand... Sorry the problem is:3/5(x+1)^5/3 + 3/4(x+1)^8/3