simplifying sqrt[1/2](sqrt[8] + sqrt[2]), sqrt[3](sqrt[6]-2s

[Jodene222]

1) sqrt[1/2](sqrt[8] + sqrt[2])

also

2) sqrt[3](sqrt[6]-2sqrt[3]

 

[stapel]

What have you tried? How far have you gotten?

For instance, for (1), after restating sqrt[1/2] as 1/sqrt[2] and sqrt[8] as 2 sqrt[2], what did you do next?

Please be complete. Thank you!

Eliz.

 

[Jodene222]

so far i have:

1/sqrt[2](3sqrt[2])

 

[stapel]

so far i have: 1/sqrt[2](3sqrt[2])

How did you get a 3sqrt[2] in the denominator? Please show all your steps.

Thank you!

Eliz.

 

[Jodene222]

after restating like you said, we added 2 sqrt[2] + sqrt[2]

or were we suppose to multiply 1/sqrt[2] times each of the above?

 

[Jodene222]

is the answer 14sqrt[3]/3

 

[Jodene222]

ignore my last post...the answer was for a different problem. still wondering if i am on the right track.

 

[stapel]

after restating like you said, we added 2 sqrt[2] + sqrt[2]

or were we suppose to multiply 1/sqrt[2] times each of the above?

So you actually meant the following?

. . . . .(1/sqrt[2])(3 sqrt[2])

...or:

. . . . .(3 sqrt[2]) / (sqrt[2])

Are you familiar with how to simplify fractions...?

Eliz.