jonnburton
Junior Member
- Joined
- Dec 16, 2012
- Messages
- 155
Hi
I have been unable to solve the following simultaneous equation and was wondering whether anyone could point me in the right direction/show what I'm doing wrong in my working.
A) 5x + 3y = 4
B) 5x^2 - 3y^2 = 8
Rearranging A:
C) 3y = 4-5x
so B is:
5x^2 - (4-5x)^2 = 8
5x^2 - (16-40x+25) = 8
-20x^2 +40x -24 = 0
And this is where I reach a dead end as the final quadratic equation is not factorizable (b^2 - 4ac = 3520).
Any information would be greatly appreciated!
I have been unable to solve the following simultaneous equation and was wondering whether anyone could point me in the right direction/show what I'm doing wrong in my working.
A) 5x + 3y = 4
B) 5x^2 - 3y^2 = 8
Rearranging A:
C) 3y = 4-5x
so B is:
5x^2 - (4-5x)^2 = 8
5x^2 - (16-40x+25) = 8
-20x^2 +40x -24 = 0
And this is where I reach a dead end as the final quadratic equation is not factorizable (b^2 - 4ac = 3520).
Any information would be greatly appreciated!