Hello if anyone has time I would appreciate if I could get som help!
Assignment
Determine A,k,v and d for the following Asin(kx-v) + d:
My question
A=2
k=2
d=3
v??
My first thought was that v=15 since the curve is shifted 15 degrees backwards. This was apparently wrong. The correct answer is 60, which is calculated by the equation 2sin(2*75-v)=5. The equation I straight forward and I understand how to derive v from this.
Could someone help me to understand the reason why the answer is 60 and not 15, and if it is possible to derive 60 from graph direct without calculating it?
Thank you for time!
Assignment
Determine A,k,v and d for the following Asin(kx-v) + d:
My question
A=2
k=2
d=3
v??
My first thought was that v=15 since the curve is shifted 15 degrees backwards. This was apparently wrong. The correct answer is 60, which is calculated by the equation 2sin(2*75-v)=5. The equation I straight forward and I understand how to derive v from this.
Could someone help me to understand the reason why the answer is 60 and not 15, and if it is possible to derive 60 from graph direct without calculating it?
Thank you for time!