Sketching Graph of y = sqrt2x+1 (Asymptotes)

daking

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Nov 1, 2007
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Could someone please help me by explaining the method in sketching this graph

y=√2x+1

could you please try to make it really basic steps i know you make x and y equal to 0 but I want to see the method after this
 
daking said:
Could someone please help me by explaining the method in sketching this graph

y=√2x+1
The "method" is the same as you used for all your other graphing: Pick x-values, plug them in, find the corresponding y-values, and draw the dots. Repeat the process until you've got enough dots to draw a good picture. The only difference is that not all radical functions continue forever at either end (as do straight lines, for instance).

daking said:
could you please try to make it really basic steps
For lessons (the "really basic steps"), please study some of the many great resources available online:

. . . . .Google results for "graphing radical functions"

daking said:
i know you make x and y equal to 0 but I want to see the method after this
I'm sorry, but I don't undertstand what you're talking about here...? Setting x and y equal to zero gives you exactly one point, (0, 0), which may or may not lie on the graph.

Please reply with clarification, including the full and exact text of the exercise (is it "sqrt[2]x + 1", "sqrt[2x] + 1', "sqrt[2x + 1", or something else? etc) and its instructions (are you graphing, finding asymptotes, or something else? etc).

Thank you! :D

Eliz.
 
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