Small question

maxhk

New member
Joined
Sep 26, 2011
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26
Hello everyone,

I have this small question :

"If a,b,c\displaystyle a, b, c are constants with ab0\displaystyle ab \neq 0, show that the graph of y=a sin(bx+c)\displaystyle y = a \ \sin(bx+c) is always concave toward the x-axis."

What does concave toward the x-axis mean ? I don't understand what am I supposed to do ?

I understand what concave upward and concave downward are.

Thanks for your help!
 
Last edited:
Hello, maxhk!

What does concave toward the x-axis mean?

When the graph is above the x\displaystyle x-axis, it is concave down.

When the graph is below the x\displaystyle x-axis, it is concave up.


Code:
    |
    |        *
    |     *     *
    |   *         *
    |  *           *
    |
- - + * - - - - - - * - - - - - - * - -
    |
    |                *           *
    |                 *         *
    |                   *     *
    |                      *
    |

The "concave side" of the graph is always toward the x\displaystyle x-axis.
 
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