• Welcome! The new FreeMathHelp.com forum is live. We've moved from VB4 to Xenforo 2.1 as our underlying software. Hopefully you find the upgrade to be a positive change. Please feel free to reach out as issues arise -- things will be a little different, and minor issues will no doubt crop up.

Solution of a quadratic parametric equation

ryloth

New member
I am trying to solve the attached quadratic parametric equation.
I have just simplify a bit the denominator by collecting a couple of terms, but I am stuck there.
Thank you a lot.


eqn01.large.jpg


Sorry for the low quality of the image.

Gianluca
 

Attachments

tkhunny

Moderator
Staff member
I am trying to solve the attached quadratic parametric equation.
I have just simplify a bit the denominator by collecting a couple of terms, but I am stuck there.
Thank you a lot.


View attachment 11006


Sorry for the low quality of the image.

Gianluca
Are you SURE it's "Quadratic"? It certainly look's quadratic in the denominators, but does that make the whole thing "quadratic"?

What do you mean by "collect"? Factoring may be a nice direction.

\(\displaystyle \dfrac{1}{(x+2k)(x-(k+1))} = \dfrac{x}{(x+2k)(x-2k)}\)

A common denominator may help you on your way.

Note: "Parametric" usually means that there is some independent variable that controls all the other variables. It doesn't normally mean that there is a arbitrary parameter included ('k' in your example). Anyway, your question was understandable.
 

ryloth

New member
Thank you very much.
Indeed I am not used to math terms (I am more confident with biochemistry) and vocabulary gives not much help.

In italian those kind of equations are defined as 'equazioni di secondo ordine parametriche'.

I was eventually able to solve it.

Gianluca
 

Subhotosh Khan

Super Moderator
I am trying to solve the attached quadratic parametric equation.
I have just simplify a bit the denominator by collecting a couple of terms, but I am stuck there.
Thank you a lot.


View attachment 11006


Sorry for the low quality of the image.

Gianluca
\(\displaystyle \displaystyle{\dfrac{1}{x^2 + (k-1)x - 2k^2 - 2k} = \dfrac{x}{x^2 - 4k^2}}\)
 
Last edited:

tkhunny

Moderator
Staff member
Thank you very much.
Indeed I am not used to math terms (I am more confident with biochemistry) and vocabulary gives not much help.

In italian those kind of equations are defined as 'equazioni di secondo ordine parametriche'.

I was eventually able to solve it.

Gianluca
Fair enough. Thanks for sharing the translation.
 
Top